X^2+2/5x=7/5

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Solution for X^2+2/5x=7/5 equation: 



X^2+2/5X=7/5

We move all terms to the left:

X^2+2/5X-(7/5)=0



Domain of the equation: 5X!=0

X!=0/5

X!=0

X∈R



We add all the numbers together, and all the variables

X^2+2/5X-(+7/5)=0

We get rid of parentheses

X^2+2/5X-7/5=0

We calculate fractions


X^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{2}=0$

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